3(z+2)-2-z=(5+z)

Solution for 3(z+2)-2-z=(5+z) equation:

Simplifying
3(z + 2) + -2 + -1z = (5 + z)

Reorder the terms:
3(2 + z) + -2 + -1z = (5 + z)
(2 * 3 + z * 3) + -2 + -1z = (5 + z)
(6 + 3z) + -2 + -1z = (5 + z)

Reorder the terms:
6 + -2 + 3z + -1z = (5 + z)

Combine like terms: 6 + -2 = 4
4 + 3z + -1z = (5 + z)

Combine like terms: 3z + -1z = 2z
4 + 2z = (5 + z)

Remove parenthesis around (5 + z)
4 + 2z = 5 + z

Solving
4 + 2z = 5 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
4 + 2z + -1z = 5 + z + -1z

Combine like terms: 2z + -1z = 1z
4 + 1z = 5 + z + -1z

Combine like terms: z + -1z = 0
4 + 1z = 5 + 0
4 + 1z = 5

Add '-4' to each side of the equation.
4 + -4 + 1z = 5 + -4

Combine like terms: 4 + -4 = 0
0 + 1z = 5 + -4
1z = 5 + -4

Combine like terms: 5 + -4 = 1
1z = 1

Divide each side by '1'.
z = 1

Simplifying
z = 1