3(z+1)=4(6-z)

Solution for 3(z+1)=4(6-z) equation:

Simplifying
3(z + 1) = 4(6 + -1z)

Reorder the terms:
3(1 + z) = 4(6 + -1z)
(1 * 3 + z * 3) = 4(6 + -1z)
(3 + 3z) = 4(6 + -1z)
3 + 3z = (6 * 4 + -1z * 4)
3 + 3z = (24 + -4z)

Solving
3 + 3z = 24 + -4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '4z' to each side of the equation.
3 + 3z + 4z = 24 + -4z + 4z

Combine like terms: 3z + 4z = 7z
3 + 7z = 24 + -4z + 4z

Combine like terms: -4z + 4z = 0
3 + 7z = 24 + 0
3 + 7z = 24

Add '-3' to each side of the equation.
3 + -3 + 7z = 24 + -3

Combine like terms: 3 + -3 = 0
0 + 7z = 24 + -3
7z = 24 + -3

Combine like terms: 24 + -3 = 21
7z = 21

Divide each side by '7'.
z = 3

Simplifying
z = 3