3(y-7)-7=-6(-4y+2)-7y

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Solution for 3(y-7)-7=-6(-4y+2)-7y equation: 



3(y-7)-7=-6(-4y+2)-7y

We move all terms to the left:

3(y-7)-7-(-6(-4y+2)-7y)=0

We multiply parentheses

3y-(-6(-4y+2)-7y)-21-7=0



We calculate terms in parentheses: -(-6(-4y+2)-7y), so:

-6(-4y+2)-7y

We add all the numbers together, and all the variables

-7y-6(-4y+2)

We multiply parentheses

-7y+24y-12

We add all the numbers together, and all the variables

17y-12

Back to the equation:

-(17y-12)



We add all the numbers together, and all the variables

3y-(17y-12)-28=0

We get rid of parentheses

3y-17y+12-28=0

We add all the numbers together, and all the variables

-14y-16=0

We move all terms containing y to the left, all other terms to the right

-14y=16

y=16/-14

y=-1+1/7

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