3(y-7)+16=0.5(4y-8)

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Solution for 3(y-7)+16=0.5(4y-8) equation: 



3(y-7)+16=0.5(4y-8)

We move all terms to the left:

3(y-7)+16-(0.5(4y-8))=0

We multiply parentheses

3y-(0.5(4y-8))-21+16=0



We calculate terms in parentheses: -(0.5(4y-8)), so:

0.5(4y-8)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We add all the numbers together, and all the variables

3y-(2y-4)-5=0

We get rid of parentheses

3y-2y+4-5=0

We add all the numbers together, and all the variables

y-1=0

We move all terms containing y to the left, all other terms to the right

y=1

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