3(y-7)+15=2(3y+6)

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Solution for 3(y-7)+15=2(3y+6) equation: 



3(y-7)+15=2(3y+6)

We move all terms to the left:

3(y-7)+15-(2(3y+6))=0

We multiply parentheses

3y-(2(3y+6))-21+15=0



We calculate terms in parentheses: -(2(3y+6)), so:

2(3y+6)

We multiply parentheses

6y+12

Back to the equation:

-(6y+12)



We add all the numbers together, and all the variables

3y-(6y+12)-6=0

We get rid of parentheses

3y-6y-12-6=0

We add all the numbers together, and all the variables

-3y-18=0

We move all terms containing y to the left, all other terms to the right

-3y=18

y=18/-3

y=-6

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