3(y-6)+8=4(y+7)

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Solution for 3(y-6)+8=4(y+7) equation: 



3(y-6)+8=4(y+7)

We move all terms to the left:

3(y-6)+8-(4(y+7))=0

We multiply parentheses

3y-(4(y+7))-18+8=0



We calculate terms in parentheses: -(4(y+7)), so:

4(y+7)

We multiply parentheses

4y+28

Back to the equation:

-(4y+28)



We add all the numbers together, and all the variables

3y-(4y+28)-10=0

We get rid of parentheses

3y-4y-28-10=0

We add all the numbers together, and all the variables

-1y-38=0

We move all terms containing y to the left, all other terms to the right

-y=38

y=38/-1

y=-38

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