3(y-5)=-6y-42

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Solution for 3(y-5)=-6y-42 equation: 



3(y-5)=-6y-42

We move all terms to the left:

3(y-5)-(-6y-42)=0

We multiply parentheses

3y-(-6y-42)-15=0

We get rid of parentheses

3y+6y+42-15=0

We add all the numbers together, and all the variables

9y+27=0

We move all terms containing y to the left, all other terms to the right

9y=-27

y=-27/9

y=-3

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