3(y-5)-2(y-4)=8

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Solution for 3(y-5)-2(y-4)=8 equation: 


Simplifying
3(y + -5) + -2(y + -4) = 8

Reorder the terms:
3(-5 + y) + -2(y + -4) = 8
(-5 * 3 + y * 3) + -2(y + -4) = 8
(-15 + 3y) + -2(y + -4) = 8

Reorder the terms:
-15 + 3y + -2(-4 + y) = 8
-15 + 3y + (-4 * -2 + y * -2) = 8
-15 + 3y + (8 + -2y) = 8

Reorder the terms:
-15 + 8 + 3y + -2y = 8

Combine like terms: -15 + 8 = -7
-7 + 3y + -2y = 8

Combine like terms: 3y + -2y = 1y
-7 + 1y = 8

Solving
-7 + 1y = 8

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 1y = 8 + 7

Combine like terms: -7 + 7 = 0
0 + 1y = 8 + 7
1y = 8 + 7

Combine like terms: 8 + 7 = 15
1y = 15

Divide each side by '1'.
y = 15

Simplifying
y = 15

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