3(y-4)=2(y+9)

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Solution for 3(y-4)=2(y+9) equation: 



3(y-4)=2(y+9)

We move all terms to the left:

3(y-4)-(2(y+9))=0

We multiply parentheses

3y-(2(y+9))-12=0



We calculate terms in parentheses: -(2(y+9)), so:

2(y+9)

We multiply parentheses

2y+18

Back to the equation:

-(2y+18)



We get rid of parentheses

3y-2y-18-12=0

We add all the numbers together, and all the variables

y-30=0

We move all terms containing y to the left, all other terms to the right

y=30

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