3(y-4)=2(-3y+36)+6

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Solution for 3(y-4)=2(-3y+36)+6 equation: 



3(y-4)=2(-3y+36)+6

We move all terms to the left:

3(y-4)-(2(-3y+36)+6)=0

We multiply parentheses

3y-(2(-3y+36)+6)-12=0



We calculate terms in parentheses: -(2(-3y+36)+6), so:

2(-3y+36)+6

We multiply parentheses

-6y+72+6

We add all the numbers together, and all the variables

-6y+78

Back to the equation:

-(-6y+78)



We get rid of parentheses

3y+6y-78-12=0

We add all the numbers together, and all the variables

9y-90=0

We move all terms containing y to the left, all other terms to the right

9y=90

y=90/9

y=10

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