3(y-4)+2(y+3)=4

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Solution for 3(y-4)+2(y+3)=4 equation: 



3(y-4)+2(y+3)=4

We move all terms to the left:

3(y-4)+2(y+3)-(4)=0

We multiply parentheses

3y+2y-12+6-4=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2

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