3(y-3)=-7y-19

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Solution for 3(y-3)=-7y-19 equation: 



3(y-3)=-7y-19

We move all terms to the left:

3(y-3)-(-7y-19)=0

We multiply parentheses

3y-(-7y-19)-9=0

We get rid of parentheses

3y+7y+19-9=0

We add all the numbers together, and all the variables

10y+10=0

We move all terms containing y to the left, all other terms to the right

10y=-10

y=-10/10

y=-1

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