3(y-3)-8=-7(-3y+3)-6y

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Solution for 3(y-3)-8=-7(-3y+3)-6y equation: 



3(y-3)-8=-7(-3y+3)-6y

We move all terms to the left:

3(y-3)-8-(-7(-3y+3)-6y)=0

We multiply parentheses

3y-(-7(-3y+3)-6y)-9-8=0



We calculate terms in parentheses: -(-7(-3y+3)-6y), so:

-7(-3y+3)-6y

We add all the numbers together, and all the variables

-6y-7(-3y+3)

We multiply parentheses

-6y+21y-21

We add all the numbers together, and all the variables

15y-21

Back to the equation:

-(15y-21)



We add all the numbers together, and all the variables

3y-(15y-21)-17=0

We get rid of parentheses

3y-15y+21-17=0

We add all the numbers together, and all the variables

-12y+4=0

We move all terms containing y to the left, all other terms to the right

-12y=-4

y=-4/-12

y=1/3

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