3(y-3)+2y=4(2y+1)

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Solution for 3(y-3)+2y=4(2y+1) equation: 



3(y-3)+2y=4(2y+1)

We move all terms to the left:

3(y-3)+2y-(4(2y+1))=0

We add all the numbers together, and all the variables

2y+3(y-3)-(4(2y+1))=0

We multiply parentheses

2y+3y-(4(2y+1))-9=0



We calculate terms in parentheses: -(4(2y+1)), so:

4(2y+1)

We multiply parentheses

8y+4

Back to the equation:

-(8y+4)



We add all the numbers together, and all the variables

5y-(8y+4)-9=0

We get rid of parentheses

5y-8y-4-9=0

We add all the numbers together, and all the variables

-3y-13=0

We move all terms containing y to the left, all other terms to the right

-3y=13

y=13/-3

y=-4+1/3

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