3(y-2)=y-32

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Solution for 3(y-2)=y-32 equation: 



3(y-2)=y-32

We move all terms to the left:

3(y-2)-(y-32)=0

We multiply parentheses

3y-(y-32)-6=0

We get rid of parentheses

3y-y+32-6=0

We add all the numbers together, and all the variables

2y+26=0

We move all terms containing y to the left, all other terms to the right

2y=-26

y=-26/2

y=-13

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