3(y-2)=2y+3-3(-3y-1)

Solution for 3(y-2)=2y+3-3(-3y-1) equation:

3(y-2)=2y+3-3(-3y-1)

We move all terms to the left:

3(y-2)-(2y+3-3(-3y-1))=0

We multiply parentheses

3y-(2y+3-3(-3y-1))-6=0


We calculate terms in parentheses: -(2y+3-3(-3y-1)), so:

2y+3-3(-3y-1)

determiningTheFunctionDomain
2y-3(-3y-1)+3

We multiply parentheses

2y+9y+3+3

We add all the numbers together, and all the variables

11y+6

Back to the equation:

-(11y+6)


We get rid of parentheses

3y-11y-6-6=0

We add all the numbers together, and all the variables

-8y-12=0

We move all terms containing y to the left, all other terms to the right

-8y=12

y=12/-8

y=-1+1/2