3(y-2)-8=68-(2y-1)

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Solution for 3(y-2)-8=68-(2y-1) equation: 



3(y-2)-8=68-(2y-1)

We move all terms to the left:

3(y-2)-8-(68-(2y-1))=0

We multiply parentheses

3y-(68-(2y-1))-6-8=0



We calculate terms in parentheses: -(68-(2y-1)), so:

68-(2y-1)

determiningTheFunctionDomain
-(2y-1)+68

We get rid of parentheses

-2y+1+68

We add all the numbers together, and all the variables

-2y+69

Back to the equation:

-(-2y+69)



We add all the numbers together, and all the variables

3y-(-2y+69)-14=0

We get rid of parentheses

3y+2y-69-14=0

We add all the numbers together, and all the variables

5y-83=0

We move all terms containing y to the left, all other terms to the right

5y=83

y=83/5

y=16+3/5

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