3(y-2)-4=-3(y-1)-3y

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Solution for 3(y-2)-4=-3(y-1)-3y equation: 



3(y-2)-4=-3(y-1)-3y

We move all terms to the left:

3(y-2)-4-(-3(y-1)-3y)=0

We multiply parentheses

3y-(-3(y-1)-3y)-6-4=0



We calculate terms in parentheses: -(-3(y-1)-3y), so:

-3(y-1)-3y

We add all the numbers together, and all the variables

-3y-3(y-1)

We multiply parentheses

-3y-3y+3

We add all the numbers together, and all the variables

-6y+3

Back to the equation:

-(-6y+3)



We add all the numbers together, and all the variables

3y-(-6y+3)-10=0

We get rid of parentheses

3y+6y-3-10=0

We add all the numbers together, and all the variables

9y-13=0

We move all terms containing y to the left, all other terms to the right

9y=13

y=13/9

y=1+4/9

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