3(y-2)-1=-2(-9y+1)-5y

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Solution for 3(y-2)-1=-2(-9y+1)-5y equation: 



3(y-2)-1=-2(-9y+1)-5y

We move all terms to the left:

3(y-2)-1-(-2(-9y+1)-5y)=0

We multiply parentheses

3y-(-2(-9y+1)-5y)-6-1=0



We calculate terms in parentheses: -(-2(-9y+1)-5y), so:

-2(-9y+1)-5y

We add all the numbers together, and all the variables

-5y-2(-9y+1)

We multiply parentheses

-5y+18y-2

We add all the numbers together, and all the variables

13y-2

Back to the equation:

-(13y-2)



We add all the numbers together, and all the variables

3y-(13y-2)-7=0

We get rid of parentheses

3y-13y+2-7=0

We add all the numbers together, and all the variables

-10y-5=0

We move all terms containing y to the left, all other terms to the right

-10y=5

y=5/-10

y=-1/2

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