3(y-2)-12y=-4(2y+7)

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Solution for 3(y-2)-12y=-4(2y+7) equation: 



3(y-2)-12y=-4(2y+7)

We move all terms to the left:

3(y-2)-12y-(-4(2y+7))=0

We add all the numbers together, and all the variables

-12y+3(y-2)-(-4(2y+7))=0

We multiply parentheses

-12y+3y-(-4(2y+7))-6=0



We calculate terms in parentheses: -(-4(2y+7)), so:

-4(2y+7)

We multiply parentheses

-8y-28

Back to the equation:

-(-8y-28)



We add all the numbers together, and all the variables

-9y-(-8y-28)-6=0

We get rid of parentheses

-9y+8y+28-6=0

We add all the numbers together, and all the variables

-1y+22=0

We move all terms containing y to the left, all other terms to the right

-y=-22

y=-22/-1

y=+22

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