3(y-2)+4(2y+5)=8

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Solution for 3(y-2)+4(2y+5)=8 equation: 



3(y-2)+4(2y+5)=8

We move all terms to the left:

3(y-2)+4(2y+5)-(8)=0

We multiply parentheses

3y+8y-6+20-8=0

We add all the numbers together, and all the variables

11y+6=0

We move all terms containing y to the left, all other terms to the right

11y=-6

y=-6/11

y=-6/11

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