3(y-2)+3=-3(y-3)-6y

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Solution for 3(y-2)+3=-3(y-3)-6y equation: 



3(y-2)+3=-3(y-3)-6y

We move all terms to the left:

3(y-2)+3-(-3(y-3)-6y)=0

We multiply parentheses

3y-(-3(y-3)-6y)-6+3=0



We calculate terms in parentheses: -(-3(y-3)-6y), so:

-3(y-3)-6y

We add all the numbers together, and all the variables

-6y-3(y-3)

We multiply parentheses

-6y-3y+9

We add all the numbers together, and all the variables

-9y+9

Back to the equation:

-(-9y+9)



We add all the numbers together, and all the variables

3y-(-9y+9)-3=0

We get rid of parentheses

3y+9y-9-3=0

We add all the numbers together, and all the variables

12y-12=0

We move all terms containing y to the left, all other terms to the right

12y=12

y=12/12

y=1

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