3(y-2)+15=-3y-(-9+6y)

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Solution for 3(y-2)+15=-3y-(-9+6y) equation: 



3(y-2)+15=-3y-(-9+6y)

We move all terms to the left:

3(y-2)+15-(-3y-(-9+6y))=0

We add all the numbers together, and all the variables

3(y-2)-(-3y-(6y-9))+15=0

We multiply parentheses

3y-(-3y-(6y-9))-6+15=0



We calculate terms in parentheses: -(-3y-(6y-9)), so:

-3y-(6y-9)

We get rid of parentheses

-3y-6y+9

We add all the numbers together, and all the variables

-9y+9

Back to the equation:

-(-9y+9)



We add all the numbers together, and all the variables

3y-(-9y+9)+9=0

We get rid of parentheses

3y+9y-9+9=0

We add all the numbers together, and all the variables

12y=0

y=0/12

y=0

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