3(y-10)+1=13(y-8)

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Solution for 3(y-10)+1=13(y-8) equation: 



3(y-10)+1=13(y-8)

We move all terms to the left:

3(y-10)+1-(13(y-8))=0

We multiply parentheses

3y-(13(y-8))-30+1=0



We calculate terms in parentheses: -(13(y-8)), so:

13(y-8)

We multiply parentheses

13y-104

Back to the equation:

-(13y-104)



We add all the numbers together, and all the variables

3y-(13y-104)-29=0

We get rid of parentheses

3y-13y+104-29=0

We add all the numbers together, and all the variables

-10y+75=0

We move all terms containing y to the left, all other terms to the right

-10y=-75

y=-75/-10

y=7+1/2

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