3(y-1)=y+1-4(-3y-1)

Solution for 3(y-1)=y+1-4(-3y-1) equation:

3(y-1)=y+1-4(-3y-1)

We move all terms to the left:

3(y-1)-(y+1-4(-3y-1))=0

We multiply parentheses

3y-(y+1-4(-3y-1))-3=0


We calculate terms in parentheses: -(y+1-4(-3y-1)), so:

y+1-4(-3y-1)

determiningTheFunctionDomain
y-4(-3y-1)+1

We multiply parentheses

y+12y+4+1

We add all the numbers together, and all the variables

13y+5

Back to the equation:

-(13y+5)


We get rid of parentheses

3y-13y-5-3=0

We add all the numbers together, and all the variables

-10y-8=0

We move all terms containing y to the left, all other terms to the right

-10y=8

y=8/-10

y=-4/5