3(y-1)=9y+9-4(-2y-1)

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Solution for 3(y-1)=9y+9-4(-2y-1) equation: 



3(y-1)=9y+9-4(-2y-1)

We move all terms to the left:

3(y-1)-(9y+9-4(-2y-1))=0

We multiply parentheses

3y-(9y+9-4(-2y-1))-3=0



We calculate terms in parentheses: -(9y+9-4(-2y-1)), so:

9y+9-4(-2y-1)

determiningTheFunctionDomain
9y-4(-2y-1)+9

We multiply parentheses

9y+8y+4+9

We add all the numbers together, and all the variables

17y+13

Back to the equation:

-(17y+13)



We get rid of parentheses

3y-17y-13-3=0

We add all the numbers together, and all the variables

-14y-16=0

We move all terms containing y to the left, all other terms to the right

-14y=16

y=16/-14

y=-1+1/7

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