3(y-1)-9=-4(-3y+4)-3y

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Solution for 3(y-1)-9=-4(-3y+4)-3y equation: 



3(y-1)-9=-4(-3y+4)-3y

We move all terms to the left:

3(y-1)-9-(-4(-3y+4)-3y)=0

We multiply parentheses

3y-(-4(-3y+4)-3y)-3-9=0



We calculate terms in parentheses: -(-4(-3y+4)-3y), so:

-4(-3y+4)-3y

We add all the numbers together, and all the variables

-3y-4(-3y+4)

We multiply parentheses

-3y+12y-16

We add all the numbers together, and all the variables

9y-16

Back to the equation:

-(9y-16)



We add all the numbers together, and all the variables

3y-(9y-16)-12=0

We get rid of parentheses

3y-9y+16-12=0

We add all the numbers together, and all the variables

-6y+4=0

We move all terms containing y to the left, all other terms to the right

-6y=-4

y=-4/-6

y=2/3

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