3(y-1)-6=-3(-5y+1)-8y

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Solution for 3(y-1)-6=-3(-5y+1)-8y equation: 



3(y-1)-6=-3(-5y+1)-8y

We move all terms to the left:

3(y-1)-6-(-3(-5y+1)-8y)=0

We multiply parentheses

3y-(-3(-5y+1)-8y)-3-6=0



We calculate terms in parentheses: -(-3(-5y+1)-8y), so:

-3(-5y+1)-8y

We add all the numbers together, and all the variables

-8y-3(-5y+1)

We multiply parentheses

-8y+15y-3

We add all the numbers together, and all the variables

7y-3

Back to the equation:

-(7y-3)



We add all the numbers together, and all the variables

3y-(7y-3)-9=0

We get rid of parentheses

3y-7y+3-9=0

We add all the numbers together, and all the variables

-4y-6=0

We move all terms containing y to the left, all other terms to the right

-4y=6

y=6/-4

y=-1+1/2

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