3(y-1)+4=2(y-1)+y+y

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Solution for 3(y-1)+4=2(y-1)+y+y equation: 


Simplifying
3(y + -1) + 4 = 2(y + -1) + y + y

Reorder the terms:
3(-1 + y) + 4 = 2(y + -1) + y + y
(-1 * 3 + y * 3) + 4 = 2(y + -1) + y + y
(-3 + 3y) + 4 = 2(y + -1) + y + y

Reorder the terms:
-3 + 4 + 3y = 2(y + -1) + y + y

Combine like terms: -3 + 4 = 1
1 + 3y = 2(y + -1) + y + y

Reorder the terms:
1 + 3y = 2(-1 + y) + y + y
1 + 3y = (-1 * 2 + y * 2) + y + y
1 + 3y = (-2 + 2y) + y + y

Combine like terms: 2y + y = 3y
1 + 3y = -2 + 3y + y

Combine like terms: 3y + y = 4y
1 + 3y = -2 + 4y

Solving
1 + 3y = -2 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
1 + 3y + -4y = -2 + 4y + -4y

Combine like terms: 3y + -4y = -1y
1 + -1y = -2 + 4y + -4y

Combine like terms: 4y + -4y = 0
1 + -1y = -2 + 0
1 + -1y = -2

Add '-1' to each side of the equation.
1 + -1 + -1y = -2 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = -2 + -1
-1y = -2 + -1

Combine like terms: -2 + -1 = -3
-1y = -3

Divide each side by '-1'.
y = 3

Simplifying
y = 3

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