3(y-1)+2(y+3)=36

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Solution for 3(y-1)+2(y+3)=36 equation: 



3(y-1)+2(y+3)=36

We move all terms to the left:

3(y-1)+2(y+3)-(36)=0

We multiply parentheses

3y+2y-3+6-36=0

We add all the numbers together, and all the variables

5y-33=0

We move all terms containing y to the left, all other terms to the right

5y=33

y=33/5

y=6+3/5

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