3(y+7/3)=36/3

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Solution for 3(y+7/3)=36/3 equation:



3(y+7/3)=36/3
We move all terms to the left:
3(y+7/3)-(36/3)=0
We add all the numbers together, and all the variables
3(+y+7/3)-12=0
We multiply parentheses
3y-12+7/3*3=0
We multiply all the terms by the denominator
3y*3*3+7-12*3*3=0
We add all the numbers together, and all the variables
3y*3*3-101=0
Wy multiply elements
27y*3-101=0
Wy multiply elements
81y-101=0
We move all terms containing y to the left, all other terms to the right
81y=101
y=101/81
y=1+20/81

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