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3(y+5)+5y=2(y-6)
We move all terms to the left:
3(y+5)+5y-(2(y-6))=0
We add all the numbers together, and all the variables
5y+3(y+5)-(2(y-6))=0
We multiply parentheses
5y+3y-(2(y-6))+15=0
We calculate terms in parentheses: -(2(y-6)), so:We add all the numbers together, and all the variables
2(y-6)
We multiply parentheses
2y-12
Back to the equation:
-(2y-12)
8y-(2y-12)+15=0
We get rid of parentheses
8y-2y+12+15=0
We add all the numbers together, and all the variables
6y+27=0
We move all terms containing y to the left, all other terms to the right
6y=-27
y=-27/6
y=-4+1/2
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