3(y+4)=4(y+1)

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Solution for 3(y+4)=4(y+1) equation:



3(y+4)=4(y+1)
We move all terms to the left:
3(y+4)-(4(y+1))=0
We multiply parentheses
3y-(4(y+1))+12=0
We calculate terms in parentheses: -(4(y+1)), so:
4(y+1)
We multiply parentheses
4y+4
Back to the equation:
-(4y+4)
We get rid of parentheses
3y-4y-4+12=0
We add all the numbers together, and all the variables
-1y+8=0
We move all terms containing y to the left, all other terms to the right
-y=-8
y=-8/-1
y=+8

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