3(y+4)=-4(2y-4)+y

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Solution for 3(y+4)=-4(2y-4)+y equation:


Simplifying
3(y + 4) = -4(2y + -4) + y

Reorder the terms:
3(4 + y) = -4(2y + -4) + y
(4 * 3 + y * 3) = -4(2y + -4) + y
(12 + 3y) = -4(2y + -4) + y

Reorder the terms:
12 + 3y = -4(-4 + 2y) + y
12 + 3y = (-4 * -4 + 2y * -4) + y
12 + 3y = (16 + -8y) + y

Combine like terms: -8y + y = -7y
12 + 3y = 16 + -7y

Solving
12 + 3y = 16 + -7y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '7y' to each side of the equation.
12 + 3y + 7y = 16 + -7y + 7y

Combine like terms: 3y + 7y = 10y
12 + 10y = 16 + -7y + 7y

Combine like terms: -7y + 7y = 0
12 + 10y = 16 + 0
12 + 10y = 16

Add '-12' to each side of the equation.
12 + -12 + 10y = 16 + -12

Combine like terms: 12 + -12 = 0
0 + 10y = 16 + -12
10y = 16 + -12

Combine like terms: 16 + -12 = 4
10y = 4

Divide each side by '10'.
y = 0.4

Simplifying
y = 0.4

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