3(y+4)=-2(4y+5)

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Solution for 3(y+4)=-2(4y+5) equation: 



3(y+4)=-2(4y+5)

We move all terms to the left:

3(y+4)-(-2(4y+5))=0

We multiply parentheses

3y-(-2(4y+5))+12=0



We calculate terms in parentheses: -(-2(4y+5)), so:

-2(4y+5)

We multiply parentheses

-8y-10

Back to the equation:

-(-8y-10)



We get rid of parentheses

3y+8y+10+12=0

We add all the numbers together, and all the variables

11y+22=0

We move all terms containing y to the left, all other terms to the right

11y=-22

y=-22/11

y=-2

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