3(y+4)-10=66-7y

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Solution for 3(y+4)-10=66-7y equation:



3(y+4)-10=66-7y
We move all terms to the left:
3(y+4)-10-(66-7y)=0
We add all the numbers together, and all the variables
3(y+4)-(-7y+66)-10=0
We multiply parentheses
3y-(-7y+66)+12-10=0
We get rid of parentheses
3y+7y-66+12-10=0
We add all the numbers together, and all the variables
10y-64=0
We move all terms containing y to the left, all other terms to the right
10y=64
y=64/10
y=6+2/5

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