3(y+4)-(y-2)=-7

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Solution for 3(y+4)-(y-2)=-7 equation: 



3(y+4)-(y-2)=-7

We move all terms to the left:

3(y+4)-(y-2)-(-7)=0

We add all the numbers together, and all the variables

3(y+4)-(y-2)+7=0

We multiply parentheses

3y-(y-2)+12+7=0

We get rid of parentheses

3y-y+2+12+7=0

We add all the numbers together, and all the variables

2y+21=0

We move all terms containing y to the left, all other terms to the right

2y=-21

y=-21/2

y=-10+1/2

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