3(y+4)+2=20

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Solution for 3(y+4)+2=20 equation: 



3(y+4)+2=20

We move all terms to the left:

3(y+4)+2-(20)=0

We add all the numbers together, and all the variables

3(y+4)-18=0

We multiply parentheses

3y+12-18=0

We add all the numbers together, and all the variables

3y-6=0

We move all terms containing y to the left, all other terms to the right

3y=6

y=6/3

y=2

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