3(y+3)=7+2y+2+y

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Solution for 3(y+3)=7+2y+2+y equation:


Simplifying
3(y + 3) = 7 + 2y + 2 + y

Reorder the terms:
3(3 + y) = 7 + 2y + 2 + y
(3 * 3 + y * 3) = 7 + 2y + 2 + y
(9 + 3y) = 7 + 2y + 2 + y

Reorder the terms:
9 + 3y = 7 + 2 + 2y + y

Combine like terms: 7 + 2 = 9
9 + 3y = 9 + 2y + y

Combine like terms: 2y + y = 3y
9 + 3y = 9 + 3y

Add '-9' to each side of the equation.
9 + -9 + 3y = 9 + -9 + 3y

Combine like terms: 9 + -9 = 0
0 + 3y = 9 + -9 + 3y
3y = 9 + -9 + 3y

Combine like terms: 9 + -9 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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