3(y+22)=12y+30

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Solution for 3(y+22)=12y+30 equation: 



3(y+22)=12y+30

We move all terms to the left:

3(y+22)-(12y+30)=0

We multiply parentheses

3y-(12y+30)+66=0

We get rid of parentheses

3y-12y-30+66=0

We add all the numbers together, and all the variables

-9y+36=0

We move all terms containing y to the left, all other terms to the right

-9y=-36

y=-36/-9

y=+4

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