3(y+2)=y-4*

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Solution for 3(y+2)=y-4* equation: 



3(y+2)=y-4*

We move all terms to the left:

3(y+2)-(y-4*)=0

We add all the numbers together, and all the variables

3(y+2)-(+y)=0

We multiply parentheses

3y-(+y)+6=0

We get rid of parentheses

3y-y+6=0

We add all the numbers together, and all the variables

2y+6=0

We move all terms containing y to the left, all other terms to the right

2y=-6

y=-6/2

y=-3

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