3(y+2)=5(y-6)=

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Solution for 3(y+2)=5(y-6)= equation: 



3(y+2)=5(y-6)=

We move all terms to the left:

3(y+2)-(5(y-6))=0

We multiply parentheses

3y-(5(y-6))+6=0



We calculate terms in parentheses: -(5(y-6)), so:

5(y-6)

We multiply parentheses

5y-30

Back to the equation:

-(5y-30)



We get rid of parentheses

3y-5y+30+6=0

We add all the numbers together, and all the variables

-2y+36=0

We move all terms containing y to the left, all other terms to the right

-2y=-36

y=-36/-2

y=+18

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