3(y+2)=4(Y+1)

Solution for 3(y+2)=4(Y+1) equation:

Simplifying
3(y + 2) = 4(Y + 1)

Reorder the terms:
3(2 + y) = 4(Y + 1)
(2 * 3 + y * 3) = 4(Y + 1)
(6 + 3y) = 4(Y + 1)

Reorder the terms:
6 + 3y = 4(1 + Y)
6 + 3y = (1 * 4 + Y * 4)
6 + 3y = (4 + 4Y)

Solving
6 + 3y = 4 + 4Y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3y = 4 + -6 + 4Y

Combine like terms: 6 + -6 = 0
0 + 3y = 4 + -6 + 4Y
3y = 4 + -6 + 4Y

Combine like terms: 4 + -6 = -2
3y = -2 + 4Y

Divide each side by '3'.
y = -0.6666666667 + 1.333333333Y

Simplifying
y = -0.6666666667 + 1.333333333Y