3(y+2)=2(y-2)

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Solution for 3(y+2)=2(y-2) equation: 



3(y+2)=2(y-2)

We move all terms to the left:

3(y+2)-(2(y-2))=0

We multiply parentheses

3y-(2(y-2))+6=0



We calculate terms in parentheses: -(2(y-2)), so:

2(y-2)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We get rid of parentheses

3y-2y+4+6=0

We add all the numbers together, and all the variables

y+10=0

We move all terms containing y to the left, all other terms to the right

y=-10

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