3(y+2)=2(y+3)+y

Solution for 3(y+2)=2(y+3)+y equation:

Simplifying
3(y + 2) = 2(y + 3) + y

Reorder the terms:
3(2 + y) = 2(y + 3) + y
(2 * 3 + y * 3) = 2(y + 3) + y
(6 + 3y) = 2(y + 3) + y

Reorder the terms:
6 + 3y = 2(3 + y) + y
6 + 3y = (3 * 2 + y * 2) + y
6 + 3y = (6 + 2y) + y

Combine like terms: 2y + y = 3y
6 + 3y = 6 + 3y

Add '-6' to each side of the equation.
6 + -6 + 3y = 6 + -6 + 3y

Combine like terms: 6 + -6 = 0
0 + 3y = 6 + -6 + 3y
3y = 6 + -6 + 3y

Combine like terms: 6 + -6 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.