3(y+2)=1

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Solution for 3(y+2)=1 equation: 



3(y+2)=1

We move all terms to the left:

3(y+2)-(1)=0

We multiply parentheses

3y+6-1=0

We add all the numbers together, and all the variables

3y+5=0

We move all terms containing y to the left, all other terms to the right

3y=-5

y=-5/3

y=-1+2/3

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