3(y+2)-y=2(y+1)+5

Solution for 3(y+2)-y=2(y+1)+5 equation:

Simplifying
3(y + 2) + -1y = 2(y + 1) + 5

Reorder the terms:
3(2 + y) + -1y = 2(y + 1) + 5
(2 * 3 + y * 3) + -1y = 2(y + 1) + 5
(6 + 3y) + -1y = 2(y + 1) + 5

Combine like terms: 3y + -1y = 2y
6 + 2y = 2(y + 1) + 5

Reorder the terms:
6 + 2y = 2(1 + y) + 5
6 + 2y = (1 * 2 + y * 2) + 5
6 + 2y = (2 + 2y) + 5

Reorder the terms:
6 + 2y = 2 + 5 + 2y

Combine like terms: 2 + 5 = 7
6 + 2y = 7 + 2y

Add '-2y' to each side of the equation.
6 + 2y + -2y = 7 + 2y + -2y

Combine like terms: 2y + -2y = 0
6 + 0 = 7 + 2y + -2y
6 = 7 + 2y + -2y

Combine like terms: 2y + -2y = 0
6 = 7 + 0
6 = 7

Solving
6 = 7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.