3(y+2)-7=2(y-3)

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Solution for 3(y+2)-7=2(y-3) equation: 



3(y+2)-7=2(y-3)

We move all terms to the left:

3(y+2)-7-(2(y-3))=0

We multiply parentheses

3y-(2(y-3))+6-7=0



We calculate terms in parentheses: -(2(y-3)), so:

2(y-3)

We multiply parentheses

2y-6

Back to the equation:

-(2y-6)



We add all the numbers together, and all the variables

3y-(2y-6)-1=0

We get rid of parentheses

3y-2y+6-1=0

We add all the numbers together, and all the variables

y+5=0

We move all terms containing y to the left, all other terms to the right

y=-5

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