3(y+2)-5(y-1)=8y+11-10y

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Solution for 3(y+2)-5(y-1)=8y+11-10y equation:


Simplifying
3(y + 2) + -5(y + -1) = 8y + 11 + -10y

Reorder the terms:
3(2 + y) + -5(y + -1) = 8y + 11 + -10y
(2 * 3 + y * 3) + -5(y + -1) = 8y + 11 + -10y
(6 + 3y) + -5(y + -1) = 8y + 11 + -10y

Reorder the terms:
6 + 3y + -5(-1 + y) = 8y + 11 + -10y
6 + 3y + (-1 * -5 + y * -5) = 8y + 11 + -10y
6 + 3y + (5 + -5y) = 8y + 11 + -10y

Reorder the terms:
6 + 5 + 3y + -5y = 8y + 11 + -10y

Combine like terms: 6 + 5 = 11
11 + 3y + -5y = 8y + 11 + -10y

Combine like terms: 3y + -5y = -2y
11 + -2y = 8y + 11 + -10y

Reorder the terms:
11 + -2y = 11 + 8y + -10y

Combine like terms: 8y + -10y = -2y
11 + -2y = 11 + -2y

Add '-11' to each side of the equation.
11 + -11 + -2y = 11 + -11 + -2y

Combine like terms: 11 + -11 = 0
0 + -2y = 11 + -11 + -2y
-2y = 11 + -11 + -2y

Combine like terms: 11 + -11 = 0
-2y = 0 + -2y
-2y = -2y

Add '2y' to each side of the equation.
-2y + 2y = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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