3(y+2)-4=-5(y+)+12

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Solution for 3(y+2)-4=-5(y+)+12 equation: 



3(y+2)-4=-5(y+)+12

We move all terms to the left:

3(y+2)-4-(-5(y+)+12)=0

We add all the numbers together, and all the variables

3(y+2)-(-5(+y)+12)-4=0

We multiply parentheses

3y-(-5(+y)+12)+6-4=0



We calculate terms in parentheses: -(-5(+y)+12), so:

-5(+y)+12

We multiply parentheses

-5y+12

Back to the equation:

-(-5y+12)



We add all the numbers together, and all the variables

3y-(-5y+12)+2=0

We get rid of parentheses

3y+5y-12+2=0

We add all the numbers together, and all the variables

8y-10=0

We move all terms containing y to the left, all other terms to the right

8y=10

y=10/8

y=1+1/4

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